acotrel said:
I have a simple question...
Good luck with that!
acotrel said:
I've heard that when using a dyno it doesn't matter what gear the bike is in. I can understand how maximum horsepower is measured, however how does a motorcycle dyno measure torque when the gearbox acts as a torque converter ?
The plain answer is; TORQUE X RPM / 5252 = HP. So, in anything other than high gear, even though you increase the torque, you reduce the rpm by equal amounts. Now, you would properly conclude that it would come out equal, and it would in a perfect world. HOWEVER, while it's true that you can use any gear when running on a chassis dyno, there's a few reasons for running high gear:
1) What usually ends up being the limiting factor is tire traction against the dyno's flywheel. As you point out, the gearbox acts as a torque multiplier in anything but high gear. Consequently, the higher the gear used, the less force (but higher RPM) is applied top the rear tire.
2) With an inertial dyno, the weight and rpm of the flywheel is figured into the dyno's software. The software takes into account RPM change that the engine goes through during a run, and compares that against how quickly the dyno flywheel accelerates. Using high gear forces the engine to labour longer against the dyno's flywheel, giving a better picture of RPM vs torque for the software to compile.
3) One of the things that makes our Nortons just a little bit faster than they should be is the fact that the design of the drivetrain effectively removes the transmission gears from the circuit whilst in high gear. Maybe only a couple of percent loss, but it adds up when racing. Consequently, high gear helps show a truer picture of actual engine horsepower without the parasitic loss incurred through the transmission. If you look at most "modern" motorcycles, the clutch is gear driven (1-2% loss), then, since the clutch is now spinning opposite direction of the engine, the final drive has to reverse that again in any and all gears (another 1-2% chopped off).
Nathan